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Anon tries programming in Java (lemmy.world)

submitted 1 week ago by LiamTheBox@lemmy.world to c/greentext@sh.itjust.works

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[–] lurklurk@lemmy.world 28 points 1 week ago (25 children)

Hello World

30 minutes of boilerplate

writing imports

$ cat <<EOF > Hello.java
public class Hello {
  public static void main(String args[]) {
    System.out.println("Hello world!");
  }
}
EOF
$ java Hello.java
Hello world!

[–] JackbyDev@programming.dev 7 points 1 week ago (9 children)

This is getting a little better nowadays.

> cat Hello.java
void main() {
    System.out.println("Hello, World!");
}
> java --enable-preview Hello.java
Hello, World!

Things to notice:

No compilation step.
No class declaration.
Main method is not public static
No String[] args.

This still uses preview features though. However, like you demonstrated already, compilation is no longer a required step for simplistic programs like this.

[–] PanArab@lemm.ee -1 points 6 days ago* (last edited 6 days ago) (5 children)

Main method is not public static

It must be somewhere under the hood. Otherwise, it wont be callable and it would require an instance of an object to call. Unless the object here is the Java environment?

No String[] args

They are just optional I'm sure, like C and C++. You still need them to read command line arguments.

All in all, these syntax improvements are welcome. I already moved on to Kotlin for Android development though.

[–] JackbyDev@programming.dev 2 points 6 days ago* (last edited 6 days ago) (1 children)

Main method is not public static

It must be somewhere under the hood. Otherwise, it wont be callable and it would require an instance of an object to call. Unless the object here is the Java environment?

No. From JEP-445:

If an unnamed class has an instance main method rather than a static main method then launching it is equivalent to the following, which employs the existing anonymous class declaration construct:
new Object() {
    // the unnamed class's body
}.main();

No String[] args

They are just optional I'm sure, like C and C++. You still need them to read command line arguments.

Without the preview feature enabled, it is not an optional part of the method signature. It specifically looks for a main(String[]) signature.

[–] PanArab@lemm.ee -4 points 6 days ago (1 children)

I am not in the mood to read a technical document, but I don’t think the resulting binary/byte code should be different between the two “hello world” programs. But then again, why not?

Without the preview feature enabled, it is not an optional part of the method signature. It specifically looks for a main(String[]) signature.

Ah ha! So that’s what’s going on here. They almost got it right. They had the potential to make a lot of the boilerplate optional or implicit under relevant circumstances, but instead the language has two explicit switchable modes.

Can I write a Java application in “preview feature”?

[–] JackbyDev@programming.dev 7 points 6 days ago* (last edited 6 days ago) (1 children)

I mentioned this uses preview features twice in the first comment regarding this, so I don't know why you're "ah ha"ing. Also you don't need to read the technical document, I've quoted the entirety of the relevant text. I provided it as a citation.

You seem confused about preview features. It's not a switchable mode to reduce boiler plate. I find the name very clear, but here is more information. From JEP-12

A preview feature is a new feature of the Java language, Java Virtual Machine, or Java SE API that is fully specified, fully implemented, and yet impermanent. It is available in a JDK feature release to provoke developer feedback based on real world use; this may lead to it becoming permanent in a future Java SE Platform.

As an example, JDK 17 added pattern matching for switch statements as a preview, and by JDK 21 it was added as a full fledged feature that doesn't require usage of the enable preview flag. Presumably in some future release of Java this feature will not require the usage of a flag.

[–] PanArab@lemm.ee -1 points 6 days ago* (last edited 6 days ago) (1 children)

It is pretty late for me. Sorry. And thank you for your patience. Repeating it three times helped.

It will be interesting to find out if the resulting binary is the same or not and what’s possible once it matured.

[–] JackbyDev@programming.dev 3 points 6 days ago

Yes, because it's genuinely not a static method. It's an instance method. Also the signature is different. It's not some sort of mere syntactic trick that translates void main() to public static void main(String[] args).

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