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Linux is a family of open source Unix-like operating systems based on the Linux kernel, an operating system kernel first released on September 17, 1991 by Linus Torvalds. Linux is typically packaged in a Linux distribution (or distro for short).

Distributions include the Linux kernel and supporting system software and libraries, many of which are provided by the GNU Project. Many Linux distributions use the word "Linux" in their name, but the Free Software Foundation uses the name GNU/Linux to emphasize the importance of GNU software, causing some controversy.

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Using a chromecast without a google account? (programming.dev)

submitted 2 months ago by 0x0@programming.dev to c/linux@lemmy.ml

15 comments fedilink hide all child comments

cross-posted from: https://programming.dev/post/19441267

I have a 2nd-gen chromecast, it's factory reset. If i plug it in all it tells me is to install the app to start configuring.

I don't have a google account not do i want to install/use google-related stuff on my phone.

My home router doesn't register any new device, which makes sense since the cast doesn't know the SSID/pass of the WiFi.

Does it try to ping some service/port? Multicast perhaps? Where would it get an IP from without authenticating?

My (wired) PC runs gentoo.

How can i get it to work in these conditions?

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[–] lolcatnip@reddthat.com 4 points 2 months ago (7 children)

Miracast is a separate, older protocol from what Chromecast uses.

[–] flashgnash@lemm.ee 2 points 2 months ago (6 children)

Imagine how much more convenient the world would be if the Chromecast protocol was open source

[–] 0x0@programming.dev 1 points 2 months ago (2 children)

Less ewaste too. Less profits for google though...

[–] flashgnash@lemm.ee 2 points 2 months ago (1 children)

If it's actually possible when my Chromecast stops being usable I'm putting Linux on it and using it to run some light weight projects (someone mentioned you can Linux them)

[–] 0x0@programming.dev 1 points 2 months ago

(someone mentioned you can Linux them)

Source?

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