this post was submitted on 28 Dec 2024
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[–] anindefinitearticle@sh.itjust.works 7 points 3 months ago* (last edited 3 months ago) (2 children)

Let's convert to metric so we can tell.

15 ft is about 5 m.

Water pressure increases by 10,000 pa per meter (rhogh, rho=1000 kg/m^3, g~10m/s^2), so total pressure is 50 kpa, or 1/2 earth atmospheric pressure.

One side of that hole has ambient pressure of 1 atm. The other side has that plus water pressure totalling 1.5 atm.

A pressure is just an energy density. Multiply by the cross-sectional area of the interface to get the energy gradient across the interface. An energy gradient is a force. We don't have a measure of the cross-sectional area of the hole, but if we expect a person to fit through let's call it 1m^2.

50 kpa = 50 kJ/m^3, so total force felt across this opening is 50kN which is the equivalent weight of five metric tons.

Size of the hole absolutely matters. If it's only the size of a fist (10cm x 10cm) then instead of 5 metric tons it's only 50 kg of equivalent weight, or about the weight of a person and easily survivable.

[–] victorz@lemmy.world 2 points 3 months ago (2 children)

Let's convert to metric so we can tell.

15 ft is about 5 m.

Water pressure increases by 10,000 pa per meter (rhogh, rho=1000 kg/m^3, g~10m/s^2), so total pressure is 50 kpa, or 1/2 earth atmospheric pressure.

This is very interesting. I like unit conversions.

What I did was just take 21-14 psi, and then converted that to bar or atm. I got a number close to ½.

I was like, half an atm? Can't be that bad? I can handle 1 full mf atm literally all mf day mf.

But I guess that's different somehow? I just don't understand how yet. If anyone would care to go into it with me... 🙏

[–] weker01@sh.itjust.works 2 points 3 months ago

Remember a vacuum does not have suction it's the air that presses things under vacuum together. One atm is actually quite a lot but we can withstand that as it's pressing at us from all sides including inside.

See this example of how strong 1 atm can be