this post was submitted on 12 Dec 2023
849 points (96.4% liked)

Memes

45726 readers
882 users here now

Rules:

  1. Be civil and nice.
  2. Try not to excessively repost, as a rule of thumb, wait at least 2 months to do it if you have to.

founded 5 years ago
MODERATORS
849
6÷2(1+2) (programming.dev)
submitted 11 months ago* (last edited 11 months ago) by wischi@programming.dev to c/memes@lemmy.ml
 

https://zeta.one/viral-math/

I wrote a (very long) blog post about those viral math problems and am looking for feedback, especially from people who are not convinced that the problem is ambiguous.

It's about a 30min read so thank you in advance if you really take the time to read it, but I think it's worth it if you joined such discussions in the past, but I'm probably biased because I wrote it :)

you are viewing a single comment's thread
view the rest of the comments
[–] atomicorange@lemmy.world 3 points 11 months ago* (last edited 11 months ago) (1 children)

I originally had the same reasoning but came to the opposite conclusion. Multiplication and division have the same precedence, so I read the operations from left to right unless noted otherwise with parentheses. Thus:

6/2=3

3(1+2)=9

For me to read the whole of 2(1+2) as the denominator in a fraction I would expect it to be isolated in parentheses: 6/(2(1+2)).

Reading the blog post, I understand the ambiguity now, but i’m still fascinated that we had the same criticism (no parentheses implies intent) but had opposite conclusions.

[–] SmartmanApps@programming.dev -2 points 9 months ago (1 children)

6/2=3

3(1+2)=9

You just did division before brackets, which goes against order of operations rules.

For me to read the whole of 2(1+2) as the denominator in a fraction

You just need to know The Distributive Law and Terms.

[–] atomicorange@lemmy.world 1 points 9 months ago (1 children)
[–] SmartmanApps@programming.dev -1 points 9 months ago

The linked article is wrong. Read this - has, you know, actual Maths textbook references in it, unlike the article.