Linux

48287 readers

647 users here now

From Wikipedia, the free encyclopedia

Linux is a family of open source Unix-like operating systems based on the Linux kernel, an operating system kernel first released on September 17, 1991 by Linus Torvalds. Linux is typically packaged in a Linux distribution (or distro for short).

Distributions include the Linux kernel and supporting system software and libraries, many of which are provided by the GNU Project. Many Linux distributions use the word "Linux" in their name, but the Free Software Foundation uses the name GNU/Linux to emphasize the importance of GNU software, causing some controversy.

Rules

Posts must be relevant to operating systems running the Linux kernel. GNU/Linux or otherwise.
No misinformation
No NSFW content
No hate speech, bigotry, etc

Related Communities

Community icon by Alpár-Etele Méder, licensed under CC BY 3.0

founded 5 years ago

MODERATORS

AgreeableLandscape@lemmy.ml

nooter692@lemmy.ml

MarcellusDrum@lemmy.ml

cypherpunks@lemmy.ml

cyclohexane@lemmy.ml

d3Xt3r@lemmy.nz

How exactly does linux use prefix length assigned to network interface? (lemmy.world)

submitted 9 months ago by akash_rawal@lemmy.world to c/linux@lemmy.ml

20 comments fedilink hide all child comments

I was exploring direct links between machines, and basically failed to break something.

I assigned IP address 192.168.0.1/24 to eth0 in two ways.

A. Adding 192.168.0.1/24 as usual

# ip addr add 192.168.0.1/24 dev eth0
# ping -c 1 192.168.0.2
PING 192.168.0.2 (192.168.0.2) 56(84) bytes of data.
64 bytes from 192.168.0.2: icmp_seq=1 ttl=64 time=0.051 ms

***
192.168.0.2 ping statistics
***
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 0.051/0.051/0.051/0.000 ms
#

B: Adding 192.168.0.1/32 and adding a /24 route

# ip addr add 192.168.0.1/32 dev eth0
# # 192.168.0.2 should not be reachable.
# ping -c 1 192.168.0.2
ping: connect: Network is unreachable
# # But after adding a route, it is.
# ip route add 192.168.0.0/24 dev eth0
# ping -c 1 192.168.0.2
PING 192.168.0.2 (192.168.0.2) 56(84) bytes of data.
64 bytes from 192.168.0.2: icmp_seq=1 ttl=64 time=0.053 ms

***
192.168.0.2 ping statistics
***
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 0.053/0.053/0.053/0.000 ms
#

Does this mean that adding an IP address with prefix is just a shorthand for adding the IP address with /32 prefix and adding a route afterwards? That is, does the prefix length has no meaning and the real work is done by the route entries?

Or is there any functional difference between the two methods?

Here is another case, these two nodes can reach each other via direct connection (no router in between) but don't share a subnet.

Node 1:

# ip addr add 192.168.0.1/24 dev eth0
# ip route add 192.168.1.0/24 dev eth0
# # Finish the config on Node B
# nc 192.168.1.1 8080 &lt;&lt;&lt; "Message from 192.168.0.1"
Response from 192.168.1.1

Node 2:

# ip addr add 192.168.1.1/24 dev eth0
# ip route add 192.168.0.0/24 dev eth0
# # Finish the config on Node A
# nc -l 0.0.0.0 8080 &lt;&lt;&lt; "Response from 192.168.1.1"
Message from 192.168.0.1

you are viewing a single comment's thread
view the rest of the comments

[–] taladar@sh.itjust.works 4 points 9 months ago (4 children)

If there is one thing we can all agree on is that we do not want to go back to writing out the subnet masks manually, especially not with IPv6 ones being 4 times as long.

[–] p1mrx@sh.itjust.works 1 points 9 months ago (3 children)

IPv6 subnet masks are long, but super easy because of hexadecimal. A bunch of Fs, then [EC8]? then a bunch of 0s.

[–] taladar@sh.itjust.works 1 points 9 months ago* (last edited 9 months ago) (2 children)

That doesn't sound right, even with hex you would still have 8 possible values (well, 6 if you don't count all 1 and all 0) for the byte where the netmask switches from 1s to 0s or only 4 (2 if you don't count all 1 and all 0) for the half-byte.

[–] p1mrx@sh.itjust.works 1 points 9 months ago (1 children)

I listed the 5 possible digits. What's missing?

[–] taladar@sh.itjust.works 2 points 9 months ago

Never mind, I didn't think it through properly earlier. Not quite sure what I was thinking at the time but probably got distracted. Obviously you have 5 possible values between 0 and 4 bits being 1.

1111 = 0xF 1110 = 0xE 1100 = 0xC 1000 = 0x8 0000 = 0x0