I meant line 2 (it's actually a joke the math professors on the writing team of the Simpsons put in there: it doesn't disprove Fermat's Theorem, but most calculators at the time didn't have the accuracy to cumpute that directly, which is kind of the joke)

[–] crapwittyname@lemm.ee 1 points 11 months ago (1 children)

Oh well spotted, you're right. I didn't twig at all.

[–] Prunebutt@feddit.de 2 points 11 months ago

There's a book on the subject by Simon Singh, where he writes about all the math jokes in the Simpsons. There are a bunch. ;)

[–] Windex007@lemmy.world 4 points 11 months ago

M(Ho)=π

(Ho)M=π

HoM=π

HoMEr

[–] WhiteRaven22@midwest.social 2 points 11 months ago* (last edited 11 months ago)

No, but you just discovered a hidden nerd-bait joke from the show's creators. One of the guys working on the show created some sort of program that could generate close-but-not-quite solutions. The one shown here isn't actually equal, but they are close enough that the difference won't show up without a more precise calculator, since both sides are roughly 6.397665635 x 10^43^.

3987^12^ + 4365^12^ = 63 976 656 349 698 612 616 236 230 953 154 487 896 987 106

4472^12^ = 63 976 656 348 486 725 806 862 358 322 168 575 784 124 416

EDIT: I should have read the other comments. Looks like I'm late to the party.

[–] jaybone@lemmy.world 1 points 11 months ago

That addition of exponents looks wrong.