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Backdoor found in widely used Linux utility breaks encrypted SSH connections (arstechnica.com)

submitted 7 months ago by Hubi@feddit.de to c/technology@lemmy.world

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The malicious changes were submitted by JiaT75, one of the two main xz Utils developers with years of contributions to the project.

“Given the activity over several weeks, the committer is either directly involved or there was some quite severe compromise of their system,” an official with distributor OpenWall wrote in an advisory. “Unfortunately the latter looks like the less likely explanation, given they communicated on various lists about the ‘fixes’” provided in recent updates. Those updates and fixes can be found here, here, here, and here.

On Thursday, someone using the developer's name took to a developer site for Ubuntu to ask that the backdoored version 5.6.1 be incorporated into production versions because it fixed bugs that caused a tool known as Valgrind to malfunction.

“This could break build scripts and test pipelines that expect specific output from Valgrind in order to pass,” the person warned, from an account that was created the same day.

One of maintainers for Fedora said Friday that the same developer approached them in recent weeks to ask that Fedora 40, a beta release, incorporate one of the backdoored utility versions.

“We even worked with him to fix the valgrind issue (which it turns out now was caused by the backdoor he had added),” the Ubuntu maintainer said.

He has been part of the xz project for two years, adding all sorts of binary test files, and with this level of sophistication, we would be suspicious of even older versions of xz until proven otherwise.

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[–] mister_monster@monero.town 21 points 7 months ago (1 children)

I don't know man. Imagine you could have ssh access to every Debian and fedora server on the planet, and all you had to do was write tests for some compression library for 2 years and sneak in a clever patch. I'd guess such an exploit is worth millions. You wouldn't work 2 years for millions of dollars?

This is sophisticated but it doesn't have to be a state actor.

[–] sugar_in_your_tea@sh.itjust.works 1 points 7 months ago

Yup. I think it's an independent hacker, probably hired by a state actor, but not a state actor themselves.

My understanding is that state actors generally look for exploits, not create them. I also think they'd be a little more clever than this.